If arc QT = (27x + 3) arc RT = (9x – 5) and RST = (102

Can somebody help me on this problem please!!

harkovskaia [24]

It is Rong the answer is 2

8 0

3 years ago

1. Kari is making copies at a local copy store of the program for her school play. She makes 52 copies and the total cost is $6.

Leona [35]

The first one is 2.78% second one is 3.8% third one is 4.5% and it will be 378

8 0

2 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205

lawyer [7]

Answer:

the probability is 0.0750

Step-by-step explanation:

The computation of the probability is shown below;

The mean of x is

= 1.5 ÷ √79

= 0.1688

Now the probability is

= P(Z < -0.3 ÷ 0.1688) + P(\bar{x} > 0.3 ÷ 0.1688)

= P(Z < -1.78) + P(Z > 1.78)

= P(Z < -1.78) + 1 - P(Z < 1.78

= 0.0375 + 1 - 0.9625

= 0.0750

hence, the probability is 0.0750

3 0

2 years ago

ISTEP IS COMING UP AND IM NOT READY!!!

AlekseyPX

> and < with the lines under it mean that they can also be equal to the constant on the other side (greater/less than or equal to)

So x <= 3 can be anything less than 3 and 3.

*the = in this inequality is the equivalent of a line

Now vice versa.

x => 3 can be anything greater than 3 and 3.

Now for the dots.

The open dots in signs are (< and >).

Basically they start at that point they are on but don't include it.

So an open dot at 3 pointing to the left means that the value is greater than 3 but does not include 3.

The closed dots in signs are (<= and =>).

They start at the point and include it.

So a closed dot a 3 pointing to the left means that the value is greater than 3 and includes 3.

Arrows.

Arrows pointing to the left mean that the values are getting bigger.

Arrows pointing to the right mean that the values are getting smaller.

ie : An arrow pointing to the left with a starting point at 3 = 3 and anything bigger, such as 4.

ie : An arrow pointing to the right with a starting point at 3 = 3 and anything smaller, such as 2.

Solve for problems.

The main concept is isolate the variable.

This basically means make the variable be lonely ^^

Use +, -, *, and /

Ex : 6x + 2 > 3

First, we would subtract 2 from both sides.

6x > 1

Then, we would divide each side by 6, leaving the x alone.

x > 1/6

And voila! x is anything greater than 1/6 but it does not include 1/6.

Hope this helps! ^^

8 0

3 years ago

Read 2 more answers

20 PTSS !!!<br> PLEASE HELPP !!

butalik [34]

Because it is extremely hard to find the area of this figure all together, it would be in our best interest to split this figure up into three different pieces: the two horizontal rectangles, and the verticle rectangle. We can find the area of all three and add them up. Be aware that there are two different ways that you can break this figure up, As shown in the attachments. I will be using the first image (the one with the tall horizontal rectangles, NOT the almost-squares).

So, we see that we have enough information to solve for the area of the left-most rectangle. Area = lw. 10 x 4 = 40, so the area is 40. Next, we have to notice, that the horizontal rectangles are also the same, so both of the areas of the two horizontal rectangles are 40.

Now, we can find the middle rectangle. We know that the length of the entire thing is 18, but it is taken up by 8 (4+4) of the horizontal triangles, so 18-8=10, so the length Is 10. We also know that the height of the horizontal rectangles is 10, so 10-3=7. Our dimensions for the rectangle are 10x7 or 70 square units. If we add them all together, 40+40+70=150.

The area is 150 square units

8 0

3 years ago

If arc QT = (27x + 3) arc RT = (9x – 5) and RST = (102 – 2) find arc RT.