The measure of CB from the given figure is 8cm
<h3>What is a triangle?</h3>
A triangle is 2 dimensional shape with 3 sides and angles. The types of triangle that we have are;
- Equilateral triangle
- Scalene triangle
- Isosceles
The given triangle is a scalene triangle since <u>none of the sides are equal</u>
From the figure shown, we can see that the mea<em>sure of DF is equivalent to CE and EB</em>
Since CB = CE + EB
Given the following parameter
DF = 4cm
CE = EB = DF = 4cm
Substitute
CB = 4cm + 4cm
CB = 8cm
Hence the measure of CB from the given figure is 8cm
Learn more on triangles here; brainly.com/question/25215131
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Answer:
<u>S': (2, 1)</u>
<u>T': (5, 3)</u>
<u>U': (1, -4)</u>
<u>S'': (1, 3)</u>
<u>T'': (4, 5)</u>
<u>U'': (0, -2)</u>
Step-by-step explanation:
Hi!
For Reflection Across the X-Axis use this :
(x, y) -> (x, - y)
So :
S': (2, 1)
T': (5, 3)
U': (1, -4)
and then the question also asks for a translation so we follow what it gave us:
S'': (1, 3)
T'': (4, 5)
U'': (0, -2)
Please ask me any questions that you still may have!
and Have a great day! :)
87 24/25.......24/25 = 0.96......answer is 87.96
224 7/10....7/10 = 0.7....answer is 224.7
686 49/50...49/50 = 0.98...answer is 686.98
Answer:
a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4
Step-by-step explanation:
for the equation
(1 + x⁴) dy + x*(1 + 4y²) dx = 0
(1 + x⁴) dy = - x*(1 + 4y²) dx
[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx
∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx
now to solve each integral
I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁
I₂= ∫[-x/(1 + x⁴)] dx
for u= x² → du=x*dx
I₂= ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ = - tan⁻¹ (x²) +C₂
then
1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C
for y(x=1) = 0
1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C
since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for π*N , we will choose for simplicity N=0 . hen an explicit solution would be
1/2 * 0 = - π/4 + C
C= π/4
therefore
1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4
