All categories

3 years ago

Help multiple choice but plz be right! Due soon

Mathematics

1 answer:

jekas [21]3 years ago

7 0

Answer:

I have no info...

Step-by-step explanation:

Listen to my new playlist! https://open.spotify.com/playlist/2OmVJb8VeE0HZtU56u6IFC

You might be interested in

The equation of the graph shown plotted in the coordinate plane is y = x + 4. What statement is not true about this graph? A. Ea

frez [133]

Definately option C

As it's mentioned y=x+4 it must be function
So in function every domain has its unique range.
Hence here the slope is not constant

The graph shown is a parabola which is not y=x+4

So option C is wrong

7 0

2 years ago

Read 2 more answers

In Triangle XYZ, measure of angle X = 49° , XY = 18°, and

marissa [1.9K]

Answer:

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

$YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X$ (1)

If we know that $X = 49^{\circ}$ , $XY = 18$ and $YZ = 14$ , then we have the following second order polynomial:

$14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}$

$XZ^{2}-23.618\cdot XZ +128 = 0$ (2)

By the Quadratic Formula we have the following result:

$XZ \approx 15.193\,\lor\,XZ \approx 8.424$

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

$XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y$

$\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}$

$Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)$

1) $XZ \approx 15.193$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 54.987^{\circ}$

2) $XZ \approx 8.424$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 27.008^{\circ}$

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

6 0

2 years ago

H(x) = –x2 + 1; Find h(–6)

babunello [35]

Answer:

h(-6)= -(-6)2+1= 12+1= 13.

5 0

2 years ago

let X = {a,b,c}, Y = {a,c,b}, Z = {a,b,b,c,c,c}. what are the elements of X, Y, and Z? how are X,Y, and Z related?

zhannawk [14.2K]

They're equal.

$X=Y=Z$

7 0

3 years ago

Read 2 more answers

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 46.0 and 56.

barxatty [35]

Answer: 0.05

Step-by-step explanation:

Given : Interval for uniform distribution : [46.0 minutes, 56.0 minutes]

The probability density function will be :-

$f(x)=\dfrac{1}{56-46}=\dfrac{1}{10}=0.1\ \ , 46$

The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-

$P(50.75$

Hence, the probability that a given class period runs between 50.75 and 51.25 minutes = 0.05

7 0

2 years ago