Answer: The plane is 6,547 feet from the closer edge of the runway.
This is a trigonometry problem that will involve setting up 2 different triangles. One going to the closer edge of the runway and the other going to the far end of the runway.
The constant between the 2 triangles is the height of the plane. You can solve for this is both triangles and set them equal to each other.
Do that will give you the equation:
x/tan(70) = (x+3000)/tan(76) where x is the distance to the closer end of the runway.
If you solve that equation, you will get x = 6547 feet.
Answer:
4.8 × 10^5
Step-by-step explanation:
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The pair of inequalities is graphed in the attachment.
The first inequality graphs as a shaded area below the dashed line y=-x+5.
The second inequality graphs as a shaded area below the solid line y=2x-1.
The solution set is the doubly-shaded area below the point where the lines intersect.
Answer:
2
Step-by-step explanation:
The slope (m) can be found using the formula ...
m = ∆y/∆x = (y2 -y1)/(x2 -x1)
= (1 -(-5))/(4 -1) = 6/3
m = 2
The slope of the line is 2.