Question

The height in feet of a baseball can be modeled by the function y=-16t^2+64t where t is the time in

Answer 1

Answer:

the ball reaches a height of 64 feet after 2 sec.

The ball is in the air 4 sec.

Step-by-step explanation:

The ball is following the path of a parabola.  The maximum height is at the vertex of the parabola.

Let (h, k) be the vertex.  h will be the time it takes to reach the maximum height, and k will be that height.

y = $-16t^{2} + 64t$

h = -b/2a = 64/(-2)(-16) = 64/32 = 2

k = -16(2)^2 + 64(2)

     -16(4) + 128

     - 64 + 128 = 64

V:  (2, 64)

So the ball reaches a height of 64 feet after 2 sec.

Let $-16t^{2} + 64t$ = 0       (0 is the height when the balls hits the ground)

-16t(t - 4) = 0

t = 0  or t = 4

The ball is in the air 4 sec.