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Evgen [1.6K]
3 years ago
14

Calculate the perimeter

Mathematics
1 answer:
kirill115 [55]3 years ago
5 0

Answer:

Its 58 centimeters

Step-by-step explanation:

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Setler [38]
First is 10 spaces, the second is 5 spaces.
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50 POINTS !!!!! HomeWorker Helperer please
Tcecarenko [31]

Answer:

1)     - 2 / (cos x + sinx)^2.

Step-by-step explanation:

1) I assume you want the derivative of (cos x - sin x) / ( cos x + sin x).

y'  =  (cosx + sinx)( -sinx - cosx) - (cosx - sinx)(-sinx + cosx)

        ---------------------------------------------------------------------------

                                 (cosx + sinx)^2

=  -sinxcosx - cos^2x - sin^2x - sinxcosx - (-sinxcosx+cos^2x+sin^2x-sinxcosx

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                                     (cosx + sinx)^2

=     -2sinxcosx - 1  - ( -2sinxcosx   + 1 )   /     (cosx + sinx)^2

=      -2sinxcosx - 1  - ( -2sinxcosx   + 1 )   /     (cosx + sinx)^2

=       - 2 / (cos x + sinx)^2.

3 0
3 years ago
Avery is tracking the height of a plant that grows at a constant rate. After the third week, the plant is 8.5 centimeters high.
Vadim26 [7]

Answer:

Original Plant was 1cm and it grew 2.5 cm per week.

Step-by-step explanation:

Using the Slope Formula (y2-y1/x2-x1)we can get how many centimeters it will grow in a week.

18.5cm-8.5cm/7-3

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On highway 77, the Dobson exit is halfway between the Mt. Airy exit and the Elkin exit. If the Elkin exit is located at (-5,-2)
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Given :

The Dobson exit is halfway between the Mt. Airy exit and the Elkin exit. If the Elkin exit is located at (-5,-2) and the Dobson exit is located at (-1,4).

To Find :

How far is it from the Elkin exit to the Mt. Airy exit.

Solution :

E(-5,-2) , D(-1 ,4 ) .

It is also given that Dobson exit is halfway between the Mt. Airy exit and the Elkin exit.

Let , location of Elkin exit is A(h,k) .

So , point D in terms of A and E is given by :

(\dfrac{h-5}{2},\dfrac{k-2}{2}) .

Comparing it with given D :

\dfrac{h-5}{2}=-1\\\\h=3 \dfrac{k-2}{2}=4\\\\k=10

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Distance between Elkin exit to the Mt. Airy exit.

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Therefore , distance between Elkin exit to the Mt. Airy exit is 12.17 units .

Hence ,this is the required solution .

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5(4v+1)


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