Question

Solve the equation (1 + x²)dy +xydx= 0​

Answer 1

Answer:

$y=\frac{c}{\sqrt[]{x^2+1} }$

Step-by-step explanation:

(1 + x²)dy +xydx= 0​

$(1+x^2)dy=-xydx\\\frac{1}{y}dy=\frac{-x}{x^2+1}dx$

Integrate both side

$lny=-\frac{1}{2} ln(x^2+1)+c\\y=\frac{c}{\sqrt[]{x^2+1} }$