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Artist 52 [7]
3 years ago
5

Daja is packing her backpack for school. Her textbook weighs 1 ¼ pounds. Her notebooks weigh ¼ pound. Her other supplies weigh ¾

pounds. How much do the contents of Daja’s backpack weigh?
Mathematics
2 answers:
Sophie [7]3 years ago
8 0

[I Put the fractions in to decimals!!]

Answer: 2 ¼

Expansion: You would do 1.25+.25+ .75 and that would equal 2.25 OR 2 ¼

Shalnov [3]3 years ago
6 0

Answer:

2 1/4 or 2.25

Step-by-step explanation:

1 1/4 + 1/4 = 1 2/4

1 2/4 + 3/4 = 2 1/4

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Step-by-step explanation:

this forms a 30 degree reference angle

and this is in the 4th quadrant

When the angle is 30 degrees, the coordinates are:

(\frac{\sqrt{3} }{2} ,-\frac{1}{2} )

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Rick buys a 1966 Mustang for $3,000, planning to restore and sell the car. He goes on to spend $9,000 restoring the car. At this
White raven [17]

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Step-by-step explanation:

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3 years ago
Which of the following is equal to 7^1/3?<br> O A. 3v7<br> B. V7.3<br> C. 7^3<br> D.v7
Shkiper50 [21]

Step-by-step explanation:

what does the ^ stand for? what number does it represent?

7 0
3 years ago
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
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