All categories

3 years ago

Given that lines a and b are parallel and that m∠4 = 128°, find m∠7.

Mathematics

2 answers:

Maurinko [17]3 years ago

5 0

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

line a and line b are two parallel lines.

and there is a transversal.

Since m∠4 = 128°

And m∠4 and m∠8 are corresponding angles.

So, m∠4 = 128° = m∠8

Now, m∠7+m∠8=180° (linear pair)

$m\angle 7+128^\circ=180^\circ\\\\m\angle 7=180^\circ-128^\circ\\\\m\angle 7=52^\circ$

Hence, Option 'c' is correct.

Salsk061 [2.6K]3 years ago

3 0

Try (c 52) i just did the test and got an 83 it did show show the answer but ik what i put down hope this helps

You might be interested in

Answer and show me how you do it please.

Virty [35]

The answer is the first one, impossible. This is because it shows that there are red and black cards, but never mentions that there are blue cards at all. This also means there are no blue cards. How could you get a blue card when there are none? It's impossible.

8 0

3 years ago

Read 2 more answers

You have a recipe that calls for 2 parts of milk for every 5 parts of flour You use 8 cups of milk How much flour do you need?

postnew [5]

Answer:

Step-by-step explanation:

6 0

3 years ago

The diagram shows a sector of a circle radius 10cm. Find the perimeter of the sector, giving your answer correct to 1 decimal pl

qwelly [4]

<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Anyway, I'll help you either way. A sector is a region of a circle between two radii. Let's assume the sector as:

$s=25\pi cm^2$

Then, we can find the central angle by the following equation:

$s=\frac{\theta}{360}\times\pi r^{2} \\ \\ r=10cm \\ \\ s=25\pi cm^2 \\ \\ \\ So: \\ \\ \frac{25\pi(360)}{10^2\pi}=\theta \\ \\ \theta = 90^{\circ}$

But:

$90^{\circ}=\frac{\pi}{2}$

Then:

$C:Perimeter \ of \ sector \\ \\ \\ C=\theta r \\ \\ C=\frac{\pi}{2}(10) \\ \\ C=5\pi cm \approx \boxed{15.7cm}$

6 0

4 years ago

Mars has m moons. The number of moons of Pluto is one more than twice the number of moons of Mars. The number of moons of Neptun

tester [92]

3m times 2 maybe I don’t know

7 0

4 years ago

Area codes have three digits. The first digit must not be 0 or 1, the middle digit must be 0 or 1, and the last digit must not b

disa [49]

There are 10 digits 0 1 2 3 4 5 6 7 8 9 if we can't use 0 and 1 then there are only 8 choices for the first digit and only 2 choices for the second digit and 10 for the third so there are 8*2*10 =160 possibilities. I think ???

4 0

3 years ago