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3 years ago

SOMEONE PLEASE HELP MEEEEEE

Mathematics

1 answer:

mylen [45]3 years ago

8 0

Answer:

y = 4x - 8

Step-by-step explanation:

As we can see from the graph, the line passes through (0, -8) and (2, 0).

(0, -8) is the y-intersect since that's where the line intersects the y-axis. So, b = -8.

Find the slope with the formula [ y2-y1/x2-x1 ]

0-(-8)/2-0

8/2

The slope is 4, so, m = 4.

Slope intercept form is found by the equation [ y = mx + b ]. With what we solved for, input it into the equation.

y = 4x - 8

Best of Luck!

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Use the identity i2 = -1 to compute the powers of i and complete the table.

mylen [45]

Hint: $\bf \begin{array}{llll}
i^{3}\to & i^2\cdot i^1\\\\

i^{4}\to & i^2\cdot i^2\\\\

i^{5}\to & i^2\cdot i^2\cdot i^1\\\\

i^{6}\to & i^2\cdot i^2\cdot i^2\\\\

i^{7}\to & i^2\cdot i^2\cdot i^2\cdot i^1\\\\

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i^{4n+1}\to & (i^4)^n\cdot i^1\\\\

i^{4n+2}\to & (i^4)^n\cdot i^2\\\\

i^{4n+3}\to & (i^4)^n\cdot i^3
\end{array}$

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3 years ago

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Step-by-step explanation:

I hope it helps

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oksano4ka [1.4K]

Answer:

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Step-by-step explanation:

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2 years ago

Find the equation, (f(x) = a(x-h)2+ k), for a parabola containing point (-1,0) and having (-3, 4) as a vertex. What is the stand

kirill115 [55]

$(h;\ k)\ -\ \text{the coordinates of the vertex}$

$\text{therefore we have:}\ f(x)=a(x+3)^2+4$

$\text{a parabola that passes through the point (-1; 0)}$

$\text{substitute the coordinates of the poin (-1; 0) to the equation}$

$(-1;\ 0)\to x=-1;\ y=0\\\\0=a(-1+3)^2+4\\\\0=a(2)^2+4\\\\0=4a+4\ \ \ |-4\\\\4a=-4\ \ \ |:4\\\\a=-1$

$f(x)=-(x+3)^2+4=-(x^2+2\cdot x\cdot3+3^2)+4=-(x^2+6x+9)+4\\\\=-x^2-6x-9+4=-x^2-6x-5$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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