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svp [43]
2 years ago
9

Solve -9.4 ≥ 1.7 x + 4​

Mathematics
1 answer:
Firlakuza [10]2 years ago
5 0

Answer:

if we are solving for x then it would be

x  ≤  − 7.88235294

:)

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X=5-3Y<br> X=2Y-10<br> Whats the answer
prohojiy [21]
X = 5 - 3y
x = 2y - 10

5 - 3y = 2y - 10
<u>  + 3y + 3y        </u>
       5 = 5y - 10
  <u>+ 10        + 10</u>
     <u>15</u> = <u>5y</u>
      5      5
       3 = y
x = 2y - 10
x = 2(3) - 10
x = 6 - 10
x = -4
(x, y) = (-4, 3)
6 0
3 years ago
Read 2 more answers
What is one plus one​
Ronch [10]

Answer:

2

Step-by-step explanation:

1+1=2

5 0
3 years ago
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What is the value of the expression? 9^2÷(-3)^0
stiv31 [10]
Step 1. Simplify 9^2 to 81
81 <span>÷ (-3)^0
Step 2. Use Rule of Zero: x^0 = 1
81 </span><span>÷ 1
Step 3. Simplify 
81</span>
5 0
3 years ago
A corporation has 11 manufacturing plants. Of these, seven are domestic and four are outside the United States. Each year a perf
nikdorinn [45]

Answer:

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

Step-by-step explanation:

Total plants = 11

Domestic plants = 7

Outside the US plants = 4

Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:

P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ

where n = total no. of trials

           x = no. of successful trials

           p = probability of success

           q = probability of failure

Here we have n=4, p=4/11 and q=7/11

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰

          = 1 - 0.16399

P(X≥1) = 0.836

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

7 0
3 years ago
Hi can you please help me<br>i cant answer this question.​
Alex_Xolod [135]

Answer:

take a actual picture maby

3 0
3 years ago
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