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3 years ago

Can someone help me please

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

3 0

If you were to compress a function vertically by a factor of n, f(x) would change to 1/n * f(x). Thus, choice C is the correct answer.

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Pls help!!!!!!!!!!!!!!!!!!

Natali [406]

Answer:

Step-by-step explanation:

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3 years ago

What is the solution to 4 1/5 x (1 1/9 x 3)

anygoal [31]

Answer:

Step-by-step explanation:

$4 \frac{1}{5} \times (1 \frac{1}{9} \times 3) \\\\= \frac{21}{5} \times ( \frac{10}{9} \times 3)\\\\=\frac{21}{5} \times( \frac{10}{3})\\\\= \frac{21 \times 10}{ 5 \times 3}\\\\=7 \times 2 \\\\= 14$

3 0

3 years ago

Phillip wanted to leave a 15% tip. Phillip's bill was $36.00. How much will he leave for a tip?

r-ruslan [8.4K]

Answer:

The tip would be $5.40.

Step-by-step explanation:

Okay so we know the total is $36.00 which makes it easier. 15% of 36 is 5.4. So he would leave $5.40 as a tip.

3 0

3 years ago

When an electron is removed the atom gets a ( ) Charge .

yulyashka [42]

Answer:

positive charge...............

5 0

3 years ago

What is the exact value of sin(105°)?<br><br><br>ANSWER - D) sqrt(2 + sqrt3)/2

Fofino [41]

Answer:

$\sin 105^{\circ} = \frac{\sqrt{6}+\sqrt {2}}{4}$

Step-by-step explanation:

We can use the following trigonometrical identity:

$\sin (\alpha - \beta) = \sin \alpha \cdot \cos \beta - \cos \alpha \cdot \sin \beta$ (1)

Where $\alpha$ , $\beta$ are angles, measured in sexagesimal degrees.

If we know that $\alpha = 135^{\circ}$ and $\beta = 30^{\circ}$ , then the value of the given function is:

$\sin 105^{\circ} = \sin 135^{\circ}\cdot \cos 30^{\circ} - \cos 135^{\circ}\cdot \sin 30^{\circ}$

$\sin 105^{\circ} = \left(\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{\sqrt{3}}{2}\right)-\left(-\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{1}{2}\right)$

$\sin 105^{\circ} = \frac{\sqrt{6}}{4}+\frac{\sqrt{2}}{4}$

$\sin 105^{\circ} = \sqrt{\frac{6}{16} }+\sqrt{\frac{2}{16} }$

$\sin 105^{\circ} = \sqrt{\frac{3}{8} }+\sqrt{\frac{1}{8} }$

$\sin 105^{\circ} = \frac{\sqrt{3}+1}{2\cdot \sqrt{2}}$

$\sin 105^{\circ} = \frac{\sqrt{6}+\sqrt {2}}{4}$

7 0

3 years ago