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laila [671]
3 years ago
15

Geometry need help........

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
<h2><u>Direct answer</u> :</h2><h2>\color{plum}\boxed{\tt Statements :}</h2>
  1. Segment AO = Segment KT
  2. Segment OR = Segment TE
  3. ∠AOR = ∠KTE
  4. △AOR≅△KTE
<h2 /><h2>\boxed{\color{plum}\tt  Reasons :}</h2>
  1. It is given.
  2. It is given.
  3. It is given.
  4. Since two sides and one incised angle is equal in both the triangles we can conclude that they are congruent under the SAS congruence criterion.

<h3>Steps to derive these statements and resons :</h3>

Given :

In triangle AOR and triangle KTE :

  • Segment AO = Segment KT
  • Segment OR = Segment TE
  • ∠AOR = ∠KTE

Since two sides and one included angle of these two triangles are equal, we can conclude that these triangles are congruent under the SAS congruence criterion.

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3 years ago
Evaluate -(3-6)(33).
kirill115 [55]

\longrightarrow{\green{  99 }} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

- (3 - 6)(33)

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(∵ -  \times  -  =  + )

=\: 99

<h3><u>Note</u>:-</h3>

\sf\pink{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♨}}}}}

7 0
3 years ago
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laiz [17]
The answers are A and C
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5 0
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City A is 25% less than population of city B so city A's population is what % of city B
Lerok [7]

City A is 25% less than population of city B. So city A's population is 75% of city B

<h3><u>Solution:</u></h3>

Given that City A is 25% less than population of city B

To find: city A's population is what % of city B

From given information,

City A is 25% less than population of city B

A = B - 25% of B

So we can write as,

A = B - \frac{25}{100} \times B\\\\A = B - 0.25B\\\\A = 0.75B

A = 0.75B can be written as,

A = \frac{75}{100}\times B

city A = 75 % of City B

Thus city A's population is 75% of city B

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