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tia_tia [17]
2 years ago
6

Which one doesn’t belong

Mathematics
2 answers:
Brilliant_brown [7]2 years ago
8 0
Its C my dude hope this helps
barxatty [35]2 years ago
3 0

Answer:

A. \: does \:belongs \:  because \:  it's \:  a \:  line \:  graph \:

B. \: does \:belongs \:  because \:  it's \:  a \:  line \:  graph \:

C. \: does \:belongs \:  because \:  it's \:  a \:  line \:  graph \:

D. \: does \: not \:belong \:  because \: it's \:  a \:  Scatter \:  Plot \:

Step-by-step explanation:

I believe and Hope my answer is correct.

Hope thai helps! (:

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A newspaper publisher wants to check its daily output of about 300,000 newspapers to be sure each includes a comics section. Exp
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Step-by-step explanation:

Number of Newspaper Published in a day = 300,000

Each news paper must include a Comic section. To check whether each newspaper has comic section or not, the publisher must make a sample Size of 500 or 1,000 will be good . That is , the publisher has to check between Sample size of  either 600 or 300 newspapers ,whether it contain a comic section or not.

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Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

#SPJ1

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