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DochEvi [55]
3 years ago
9

A broken rectangular-shaped window is being replaced. It measures 24 inches by 182

Mathematics
1 answer:
grigory [225]3 years ago
5 0

Answer: 432 or 4368

Step-by-step explanation:

multiply base and height this case 24,18. 24x18=432 or 182 x 24=4368

if you using 24 x 18 =432

if you using 182x24=4368

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Bruno brought 96 pounds of sugar for his bakery. Everyday he used the same amount of sugar to make bakery items. After 10 days,
deff fn [24]
96-15.2 = 80.8 pounds total used

80.8/10 = 8.08 pds used each day
8 0
3 years ago
Read 2 more answers
The Wanting Recognition (WR) Scale provides a quantitative measure of a person's level of need for approval and sensitivity to s
levacccp [35]

Answer:

<em> 99% of the confidence level  of the mean WR score for all convicted drug dealers </em>

<em>(37.4544, 40.5456)</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the sample size 'n' = 100

Given that the mean of the sample(x⁻) = 39

Given a standard deviation of the sample (σ) = 6

Level of significance = 0.01 or 99%

<u><em>Step(ii):-</em></u>

<em> 99% of the confidence level  of the mean WR score for all convicted drug dealers </em>

<em></em>(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } ,x^{-} + Z_{0.01} \frac{S.D}{\sqrt{n} })<em></em>

<em></em>(39 -2.576 \frac{6}{\sqrt{100} } ,39 + 2.576 \frac{6}{\sqrt{100} })<em></em>

<em>(39 - 1.5456 , 39+1.5456)</em>

<em>(37.4544, 40.5456)</em>

<u><em>Final answer:-</em></u>

<em> 99% of the confidence level  of the mean WR score for all convicted drug dealers </em>

<em>(37.4544, 40.5456)</em>

<em></em>

8 0
3 years ago
Need help please!!! <br> “ALL THE YOUNG DUDES” “CARRY THE NEWSSSS””
Black_prince [1.1K]

Answer:

288 cubic feet

Step-by-step explanation:

add the 3 blocks.

block 1: 12*6*2=12*12=144

block 2: (12-4)*2*6=8*2*6=8*12=96

block 3: (12-4-4)*6*2=4*12=48

add them up:

144+96+48

288 cubic feet

with help of calculator

8 0
3 years ago
Peter and his neighbor, Juan walk 2 miles to school each day yesterday peter walked to school in 27 minutes Juan walked the firs
a_sh-v [17]

Total distance from their home to school is 2 miles.

Peter covered this distance in 27 minutes yesterday. Since the rate of walking is the same today, Peter will arrive in school in 27 minutes today.

Juan covered 1 mile in 11 minutes yesterday. This means she will cover 2 miles in 22 minutes. Since the rate(speed) of walking of Jaun is also same as that of yesterday, Juan will reach the school in 22 minutes.

Thus, we can conclude that if Peter and Juan leave at the same time, Juan will reach the school 5 minutes earlier than Peter.

8 0
3 years ago
2. The Hereford Cattle Society says that the mean weight of a one-year-old Hereford bull is 1135 pounds, with a standard deviati
Andrews [41]

Answer:

16.35% probability their combined weight exceeds 46000 pounds.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 1135, \sigma = 97, n = 40, s = \frac{97}{\sqrt{40}} = 15.34

Find the probability their combined weight exceeds 46000 pounds.

This is 1 subtracted by the pvalue of Z when X = \frac{46400}{40} = 1150. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1150 - 1135}{15.34}

Z = 0.98

Z = 0.98 has a pvalue of 0.8365

1 - 0.8365 = 0.1635

16.35% probability their combined weight exceeds 46000 pounds.

5 0
3 years ago
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