Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer:
17
Step-by-step explanation:
15*15+8*8=289
= 17
Answer:
7⅓
Step-by-step explanation:
2 ÷ 3⁄11 → 2 × 3⅔ >> 7⅓
Dividing by a fraction is the exact same as multiplying by its multiplicative inverse.
* 3⅔ = 11⁄3
* 7⅓ = 22⁄3
I am joyous to assist you anytime.
(3/5)³
=(3³)/(5³)
=27/125
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As:
3*3*3=27
And:
5*5*5=125
