Let <em>x</em> be the first number in the sequence. Then the first three numbers are
{<em>x</em>, <em>x</em> + 3, <em>x</em> + 6}
The next sentence says that the sequence
{<em>x</em> + 1, <em>x</em> + 9, <em>x</em> + 25}
is geometric, which means there is some fixed number <em>r</em> for which
<em>x</em> + 9 = <em>r</em> (<em>x</em> + 1)
<em>x</em> + 25 = <em>r</em> (<em>x</em> + 9)
Solve for <em>r</em> :
<em>r</em> = (<em>x</em> + 9)/(<em>x</em> + 1) = (<em>x</em> + 25)/(<em>x</em> + 9)
Solve for <em>x</em> :
(<em>x</em> + 9)² = (<em>x</em> + 25) (<em>x</em> + 1)
<em>x</em> ² + 18<em>x</em> + 81 = <em>x</em> ² + 26<em>x</em> + 25
8<em>x</em> = 56
<em>x</em> = 7
Then the three numbers are
{7, 10, 13}
Answer:
30
Step-by-step explanation:
x(y+4) x=5 and y=2
so substitute the values for the variables
5(2+4)
Order of Operations : Parentheses first
5(6)
=30
or distributive property
5(2) +5(4)
10+20
=30
You get the same answer anyway.
Hope this helped :)
Answer:
is the answer
Step-by-step explanation:
Equation of the line: y = 6/5x + 1
= 5y = 6x + 5
= 6x - 5y + 5
Equation of the perpendicular line: bx - ay + k = 0
= -5x -6y + k = 0
Equation passes through (6,-6),
-5(6) -6(-6) + k = 0
-30 + 36 + k = 0
6 + k = 0
k = -6
Substituting,
-5x -6y + k = 0
-5x -6y -6 = 0
-6y = 5x + 6
(Slope-Intercept form)
Answer:
No I don't think you can make a graph on here. Sorry