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Arisa [49]
3 years ago
10

TransversalsFind the value of x.​

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

look at the picture I sent

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Help me please with this<br> Simplify.<br><br> 5a-12a
Oduvanchick [21]
It helps to imagine the variable a sort of as a unit. Like with 5 minus 12 lemons, it has no bearings on the addition/subtraction here.

Factor out a and subtract.

5a-12a \\ (5-12)a \\ \boxed{-7a}
4 0
3 years ago
Would anyone mind helping me
oksian1 [2.3K]

Answer:

29

Step-by-step explanation:

0.11v=3.19

\frac{0.11x}{0.11} =\frac{3.19}{0.11}

Divide:

3.19÷0.11=29

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2 years ago
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Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
Please help me with question 10.
Ludmilka [50]
I think the answer the answer/question is letter C
5 0
2 years ago
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Least two digit number exactly divisible by 6<br>​
sp2606 [1]

Answer:

2 and 3

Step-by-step explanation:

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2 years ago
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