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Kitty [74]
3 years ago
5

What are transformations in graphing quadratics

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0

Answer:

graph the equation by transforming the "parent graph" accordingly. ... For example, for a positive number c , the graph of y=x2+c is same as graph y=x2 shifted c units up. Similarly, the graph y=ax2 stretches the graph vertically by a factor of a .

Step-by-step explanation:

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The distance between Lexington and Fayetteville is 2/3 as long as the distance between Lexington and booneville .If Lexington is
Fantom [35]

Answer:

The answer to your question is: 72 miles

Step-by-step explanation:

Data

Distance from Lexington from Fayetteville = 2/3 as distance Lexington and Booneville.

Distance Lexington to Fayetteville = 108 miles

Process

                       108 / 3 = 36 miles

                       36 x 2 = 72 miles

2/3 of 108 miles is 72 miles

The distance from Lexington to Fayetteville = 72 miles                      

3 0
3 years ago
Solve for x. <br><br> 4/5(15x+20)−7x=5/6(12x−24)+6<br><br><br><br> Enter your answer in the box.
dmitriy555 [2]
The answer to the question

5 0
3 years ago
Read 2 more answers
Casey wants to buy some instruments for his niece and nephew. He has $40 to spend. Based on the prices listed below, what is the
Maksim231197 [3]
$37 because when uu add the tambourine and xylophone uu get $37.45 but we have to round to the nearest dollar and the nearest dollar is 7 and the number next to it is not 5 or higher so we turn it to 0’s and uu get $37 .
6 0
3 years ago
Help please!!!!!!!!!!!!!!!!!
krok68 [10]
C. 0.25 because you divide 0.06 by 0.24
5 0
3 years ago
How do you write a polynomial in standard form that represents the area of the shaded region of a rectangle when on the outside
-BARSIC- [3]
F ( x ) = ( x + 7 ) ( x + 4 ) - ( x + 5 ) ( x + 2 ) =
= ( x² + 4 x + 7 x + 28 ) - ( x² + 2 x + 5 x + 10 ) = 
= ( x² + 11 x + 28 ) - ( x² + 7 x + 10 ) =
= x² + 11 x + 28 - x² - 7 x - 10 = 4 x + 18
Answer:
The area of the shaded region is 4 x + 18.
8 0
3 years ago
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