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PSYCHO15rus [73]

4 years ago

9

What is the circumference of this circle?

1 answer:

Mrac [35]4 years ago

3 0

Answer:

B) 12.56

Step-by-step explanation:

The formula for circumference of a circle is 2πr.

Substitute r for 2 and it becomes 4π.

4π ≈ 12.56

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Help me please, its mathwatch

mars1129 [50]

Answer:

<h2>60 cm^2</h2>

Solution,

Let ,

a = 13

b = 13

c= 10

then,

s = a + b + c /2

= 13 + 13 + 10 / 2

= 36/2

= 18

Now,

Area of triangle:

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{18(18 - 13)(18 - 13)(18 - 10)}$

$\sqrt{18 \times 5 \times 5 \times 8}$

$\sqrt{3600}$

$60 \: {cm}^{2}$

Hope this helps ....

Good luck on your assignment...

6 0

4 years ago

What is the length of the line segment with endpoints (11,−4) and (−12,−4) ?

statuscvo [17]

Distance = √[(-12 - 11)^2 +(-4 - (-4))^2]
= √(529+0)
= 23

answer
<span>length of the line segment = 23</span>

6 0

4 years ago

Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

4 0

3 years ago

What is it<br><img src="https://tex.z-dn.net/?f=ee" id="TexFormula1" title="ee" alt="ee" align="absmiddle" class="latex-formula"

DedPeter [7]

Answer:

EE (formerly Everything Everywhere) is a British mobile network operator and internet service provider, which is a brand within the BT Group.

Parent: BT Group, BT Consumer

Subsidiary: Mobile Broadband Network Limited

Step-by-step explanation:

7 0

3 years ago

Allison has a poster that is 15 in by 18 in. What will the dimensions of the poster be if she scales it down by a factor of one-

vova2212 [387]

The dimensions will be 5 in by 6 in

you would divide the numbers by 3 and thats what u would get
Hope I helped ;)

6 0

3 years ago

Read 2 more answers