5(4)+6(5)^2-(4)^3
20+150-64
170-64=106
5 sides
each side is 15
perimiter is distance around the shape or the legnth of the sides added up
5 of them
15
5 times 15=75
75 inches
1. -> B. ;
2. -> C. ;
3. -> B. ;
4. -> A.. ;
I'm guessing the last value you have down there that got cut off was the one we want. We need to set up the general form of the absolute value equation and then solve it for a:
![y=a[x-h]+k](https://tex.z-dn.net/?f=y%3Da%5Bx-h%5D%2Bk)
. I have no absolute value symbols so I just used brackets. We have a vertex (h, k) of (0, 0) and I picked a point on the graph to use as my x and y coordinates (4, 3). Let's fill in the equation now:
![0=a[0-4]+3](https://tex.z-dn.net/?f=0%3Da%5B0-4%5D%2B3)
. We will subtract 3 from both sides leaving -3 = a[-4]. The absolute value of -4 is 4 so now we have -3 = 4a. Divide by 4 to solve for a.

. So our equation is