Is 0 > -3 true jinibuuuuuuuubjjjjjjjjjjiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

2 answers:

5 0

Answer:

Yes.

Explanation:

0 is greater than -3 because -3 is below 0 on the number scale.

-3 is a negative number. Negative numbers are below 0.

0 > -3 is correct.

<em>Hope this is correct, have a great day!</em>

Vilka [71]3 years ago

4 0

Answer:

yesssshhhh, correct it is, i think maybe, lol

Step-by-step explanation:

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IceJOKER [234]

Answer:

I think it's 4)

Step-by-step explanation:

I I haven't done too much money going to subject but I have a good idea on it

3 0

3 years ago

Slav-nsk [51]

Step-by-step explanation:

a) Give two pairs which are in the relation $\equiv \mod 4$ and two pairs that are not.

As stated before, a pair $(x,y)\in \mathbb{Z}\times\mathbb{Z}$ is equal mod m (written $x\equiv y\mod m$ ) if $m\mid (x-y)$ . Then:

b) Show the $\equiv \mod m$ is an equivalence relation.

An equivalence relation is a binary relation that is reflexive, symmetric and transitive.

By definition $\equiv \mod m$ is a binary relation. Observe that:

Reflexive. We know that, for every m, $m\mid 0$ . Then, by definition, $x\equiv x \mod m$ .
Symmetry. It is clear that, given x,y and m such that $m\mid (x-y)$ , then $m\mid (y-x)$ . Therefore $x\equiv y \mod m \iff y\equiv x \mod m$
Transitivity. Let x,y,z and m such that $x\equiv y \mod m$ and $y\equiv z \mod m$ . Then, $m\mid (y-x)$ and $m\mid (z-y)$ . Therefore: