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AleksAgata [21]

2 years ago

11

Thirty students at Eastside High School took the SAT on the same Saturday. Their raw scores are given next. 1,450 1,620 1,800 1,

740 1,650 1,800 2,010 1,780 1,840 1,490 1,620 1,480 2,390 1,640 1,830 1,710 1,900 1,910 1,950 1,820 1,590 2,350 2,260 1,870 1,530 1,950 2,000 1,830 1,980 2,100 Consider a frequency distribution of the data that groups the data in classes of 1400 up to 1600, 1600 up to 1800, 1800 up to 2000, and so on. How many students scored at least 1700 but less than 2100

1 answer:

IRISSAK [1]2 years ago

8 0

Answer:

Number of students who scored atleast 1700 but less Than 2100 = 17

Step-by-step explanation:

Given the data :

1,450 1,620 1,800 1,740 1,650 1,800 2,010 1,780 1,840 1,490 1,620 1,480 2,390 1,640 1,830 1,710 1,900 1,910 1,950 1,820 1,590 2,350 2,260 1,870 1,530 1,950 2,000 1,830 1,980 2,100

Class interval __ Frequency

1400 - 1599 ____ 5

1600 - 1799 ____ 7

1800 - 1999 ____12

2000 - 2199 ___ 3

2200 - 2399 ___ 3

Number of students who scored atleast 1700 but less Than 2100 = 17

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3 years ago

What statement is true?

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Answer:

$\frac{18}{32}>\frac{16}{32}$

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1. $\frac{14}{21}>\frac{17}{24}$

Now On solving we get;

$\frac{14}{21} = 0.66$

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So we can see that 0.70 > 0.66

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2. $\frac{18}{32}>\frac{16}{32}$

Now On solving we get;

$\frac{18}{32}=0.5625$

$\frac{16}{32}= 0.5$

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3. $\frac{20}{15}$

Now On solving we get;

$\frac{20}{15} = 1.33$

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So we can see that 1.33 > 1.2

Hence The given statement is False.

4. $\frac{29}{35}$

Now On solving we get;

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3 years ago

Ares of a rectangular floor of your house is Ax+5x-2. if the length is x+2 units, find A

Snezhnost [94]

Answer:

A=4.

Step-by-step explanation:

Note: In the expression of area the first term should be $Ax^2$ .

It is given that area of a rectangular floor of your house is $Ax^2+5x-2$ and the length is $(x+2)$ units.

We know that, area of a rectangle is

$Area=length\times width$

Since length of the rectangle is $(x+2)$ , therefore $(x+2)$ is a factor of $Ax^2+5x-2$ and the value of $Ax^2+5x-2$ is 0 at x=-2.

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Therefore, the value of A is 4.

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3 years ago