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Misha Larkins [42]
3 years ago
9

HELPPPPPP AHHH PLAESEEEEEEE

Mathematics
2 answers:
weqwewe [10]3 years ago
4 0

Answer:

The answer is D 3x+y=1 and 3x-2y=16

Step-by-step explanation:

Vadim26 [7]3 years ago
3 0
Correct ^^^^ I just checked!
You might be interested in
Segments PR and QT are diameters of Circle A.
Dafna11 [192]

Answer:

C. 320

Step-by-step explanation:

Given:

  • PR and QT are diameters

As we can see in the photo, PR and QR are perpendicular with each other at the angle PAQ => the angle QAR = 90°

=> arc PR = 360°/2 = 180°

=> mTAU = 180° - mRAS -mSAT - mPAU = 180° - 50° + 40° + 40° = 50°

Hence,  mPRU = mRAS + mSAT + mTAU + arc PQ

= 50° + 40° + 50° + 180°

= 320°

6 0
4 years ago
Ifƒ(x ) = 3x + 1 and ƒ -1 = (x-1)/3,<br> then ƒ(2) =<br><br> A) 1/3<br> B) 1<br> C) 7
Vikentia [17]

The problem gave us the equation for f(x), which was f(x) = 3x + 1. To find f(2), we can simply substitute 2 in for x, as shown below:

f(2) = 3(2) + 1 = 7


The answer is f(2) = 7.

7 0
4 years ago
Suppose that we test the hypotheses LaTeX: H_0 H 0 : LaTeX: \mu=50 μ = 50 LaTeX: H_a H a : LaTeX: \mu&gt;50 μ &gt; 50 Further su
s344n2d4d5 [400]

Answer: 0.0108

Step-by-step explanation:

Given : H_0:\mu=50\\\\H_a:\mu>50

Since the alternative hypotheses is right-tailed, so the test is a right-tailed test.

Sample size : n=30

The degree of freedom for t-distribution= =n-130-1=29

The by using the normal t-distribution table , we have

The P-value corresponds to t-statistic vale 2.43 and degree of freedom 29 , is 0.01075997 i.e. approximately 0.0108

6 0
3 years ago
Anyone mind helping?
vlabodo [156]

Answer:

87 degrees

Step-by-step explanation:

9x+6 + 7x-2 = 148

16x+4 = 148

16x = 144

x = 9

Plug into 9x+6

9(9)+6 = 87

5 0
4 years ago
Working together, it takes two different sized hoses 35 minutes to fill a small swimming pool. If it takes 60 minutes for the la
almond37 [142]

L = rate of the large hose

S = rate of the small hose

we know the sum of their rates deliver the swimming pool filled up in 35 minutes, thus L + S = 35.

now, the large hose can do it in 60 minutes, that means that in 1 minute, the large hose has only done 1/60 th of the work.

the small hose can do the whole thing in S minutes, that means in 1 minute it has only done 1/S th of the whole work.

and since both of them working together can do it in 35 minutes, then in 1 minute they both have done 1/35 th of the whole job.

\bf \stackrel{\textit{large's rate in 1 minute}}{\cfrac{1}{L}}+\stackrel{\textit{small's rate in 1 minute}}{\cfrac{1}{S}}=\stackrel{\textit{done in 1 minute}}{\cfrac{1}{35}} \\\\\\ \cfrac{1}{60}+\cfrac{1}{S}=\cfrac{1}{35}\implies \cfrac{S+60}{60S}=\cfrac{1}{35}\implies 35S+2100=60S\implies 2100=25S \\\\\\ \cfrac{2100}{25}=S\implies 84=S

8 0
4 years ago
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