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kobusy [5.1K]
2 years ago
14

PLEASE HELPPP it's Use Pythagorean theorem to find right triangle side lengths

Mathematics
2 answers:
Travka [436]2 years ago
8 0

Answer:

sqr(58)

Step-by-step explanation:

a^2+b^2=c^2

3^2+7^2=x^2

9+49=x^2

58=x^2

x=sqr(58)

Alja [10]2 years ago
3 0

Step-by-step explanation:

Hey I saw ur thing that you just posted and I dont have a great meme but please give me brainliest hehehe

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What is the slope of (-3,4) and (5,8)
vladimir1956 [14]

Answer:

m = 1/2

Step-by-step explanation:

Use the slope formula to find the slope <em>m</em>.

y2 - y1 / x2 - x1

8 - 4 / 5 - (-3) two negatives turn into positive.

8 - 4 / 5 + 3

4 / 8 = 1/2

4 0
3 years ago
70 - q - q - 2q = 80???
Aneli [31]


70-q-q-2q= 80

combine like terms first

so you get 70-4q= 80

subtract 70 on both sides and you get -4q= 10

divide -4 on both sides and you get q= 10/-4 or -2.5

3 0
3 years ago
The chef at a restaurant bought 37 pounds of salad for $46.25. How much did she pay for 1 pound of salad? Show all work and expl
Art [367]

Answer:

$1,25

Step-by-step explanation:

$46.25 : 37 = $1,25

I divided the amount of money into the number of 37 pounds

3 0
3 years ago
Read 2 more answers
Use the elimination method to solve the following system of equations.
aliya0001 [1]
The answer 
<span>2x - y + z = -3          (1)
2x + 2y + 3z = 2       (2)
3x - 3y - z = -4          (3)

</span> (1) - (2)              3y +2z =5
 3 .(1) - 2.(2)       3y+5z = -1<span>

let 's solve 
</span>3y +2z =5
3y+5z = -1<span>
z= - 2, and 3y =5+4=9,  y=3, so  </span>2x - 3 -2 = -3 implies x= 1
<span>
finally x=1, y=3 and z= -2
proof 
</span>2x - y + z = -3??     2.1 - 3 -2 = -3  (true)<span>

</span>
3 0
3 years ago
How can you tell from the equation of a rational function if the function has a hole in the graph ( a removable discontinuity) a
Eva8 [605]

Consider that,

x^2+4x+4 = (x+2)(x+2)

x^2+7x+10 = (x+2)(x+5)

Dividing those expressions leads to

(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)

The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.

5 0
2 years ago
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