Answer:
the average number of car(s) in the system is 1
Step-by-step explanation:
Given the data in the question;
Arrival rate; λ = 2.5 cars per hour
Service time; μ = 5 cars per hour
Since Arrivals follows Poisson probability distribution and service times follows exponential probability distribution.
Lq = λ² / [ μ( μ - λ ) ]
we substitute
Lq = (2.5)² / [ 5( 5 - 2.5 ) ]
Lq = 6.25 / [ 5 × 2.5 ]
Lq = 6.25 / 12.5
Lq = 0.5
Now, to get the average number of cars in the system, we say;
L = Lq + ( λ / μ )
we substitute
L = 0.5 + ( 2.5 / 5 )
L = 0.5 + 0.5
L = 1
Therefore, the average number of car(s) in the system is 1
Based on the fact that he added three correct questions, Levi is wrong in assuming that the ratio of correct answers to total answers remained the same.
<h3>Why is Levi wrong?</h3><h3 />
When the total number of variables being compared in a ratio changes, the ratio itself will change.
This means that Levi is wrong in assuming that the ratio of correct answers to total questions will remain the same after he added 3 questions to both measures.
The first ratio of correct answers to questions was:
8 : 10
4 : 5
After three correct answers are added, it becomes:
11 : 13
This is not the same as the first ratio of 4 : 5.
Find out more on ratios at brainly.com/question/17429159
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I would say Median but thats from lowest to highest not highest to lowest so I'm not sure :/
Answer:
3.54% probability of observing at most two defective homes out of a random sample of 20
Step-by-step explanation:
For each house that this developer constructs, there are only two possible outcomes. Either there are some major defect that will require substantial repairs, or there is not. The probability of a house having some major defect that will require substantial repairs is independent of other houses. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
30% of the houses this developer constructs have some major defect that will require substantial repairs.
This means that 
If the allegation is correct, what is the probability of observing at most two defective homes out of a random sample of 20
This is 
when n = 20. So
3.54% probability of observing at most two defective homes out of a random sample of 20
