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Ghella [55]
3 years ago
15

Step 1: pick a number

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0
If I pick n, it becomes 50(2n+5)+1764-2001 this is the expression
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If p(x) = X squared -1 and q(x) = 5(x-1), which expression is equivalent to (p-q)(x)
hram777 [196]
Minus the functions
(p-q)(x)=p(x)-q(x)
p(x)=x^2-1
q(x)=5(x-1)

p(x)-q(x)=x^2-1-5(x-1)
p(x)-q(x)=x^2-1-5x+5
p(x)-q(x)=x^2-5x+4
(p-q)(x)=x^2-5x+4
or factored
(p-q)(x)=(x-4)(x-1)

8 0
3 years ago
Given the monomial 2x^3 what is the coefficient?
Sveta_85 [38]

Answer:

2

Step-by-step explanation:

Big Brain

3 0
3 years ago
Read 2 more answers
I really need an answer its multiple choice
Alexxandr [17]

Answer:

a

Step-by-step explanation:

just plug in

5 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
(27^-x+3)(9^x+1)=81 what is answer?
Leni [432]
(27⁽⁻ˣ⁺³⁾) (9⁽ˣ⁺¹⁾) = 81

Instead of using logarithmic to find x, Notice that 27, 9 and 81 are the perfect powers of 3. Since 27 = 3³, 9 = 3², and 81 = 3⁴, so

(3³⁽⁻ˣ⁺³⁾) (3²⁽ˣ⁺¹⁾) = 3⁴
3³⁽⁻ˣ⁺³⁾⁺²⁽ˣ⁺¹⁾ = 3⁴

If the bases are the same, then cancel it and bring the power as a new base.
3(-x+3) + 2(x+1) = 4
-3x + 9 + 2x + 2 = 4
-x + 11 = 4
-x = 4 - 11
-x = -7
x = 7
6 0
3 years ago
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