Given that two digit numbers are used and one digit is drawn randomly.
Sample space = {10,11,...99}
n(S) = 90
32 is only one number favorable
Hence P(32) = 1/90
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Odd numbers are exactly 45.
Hence prob (odd number) = 45/90 = 1/2
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Multiples of 5 are 10,15,.....95
There are exactly 18 numbers.
Hence P(a multiple of 5) = 18/90 =1/5
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Answer:
28 percent
Step-by-step explanation:
i dont know the rest
Answer:
998
Step-by-step explanation:
I haven't included the <em><u>1</u></em> or the <em><u>1000</u></em>
Answer:
8/9 8 to 9
Step-by-step explanation:
