F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
Answer:
4a + 2b + 1/4 c.
Step-by-step explanation:
1/4(16a+8b+c)
= 1/4 * 16a + 1/4 * 8b + 1/4 * c
= 4a + 2b + 1/4 c.
(2,88)
(6,64)
(9,46)
(15,10)
first find y=mx+b
88=-6(2)+b
b=100
y=-6x+100
then plug for y and solve for x or vise versa.
Hopes this loves
