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Serggg [28]
3 years ago
8

Help me, witch are the true!!!?

Mathematics
1 answer:
Softa [21]3 years ago
8 0

Answer:

A is the answer hope this helps

You might be interested in
The cost of 21 articles is equal to selling price of 18 articles. find the profit or loss percent.​
Alex_Xolod [135]

Answer:

If all the items are sold, the profit percentage is 14.28%.

Step-by-step explanation:

Given that the cost of 21 articles is equal to selling price of 18 articles, to find the profit or loss percent the following calculation must be performed:

21 = 100

21 - 18 = X

21 = 100

3 = X

(3 x 100) / 21 = X

300/21 = X

14.28 = X

Therefore, if all the items are sold, the profit percentage is 14.28%.

3 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B8ux%5E%7B5%7D%20%7D%20%5Csqrt%7B2ux%7D" id="TexFormula1" title="\sqrt{8ux^{5} } \sqr
lozanna [386]

Answer:

4ux³

Step-by-step explanation:

√8ux⁵ √2ux

√8*2 u*u x⁵*x

√16u²x⁶

4ux³

3 0
3 years ago
Please guys help me I need help to get an A+
Sergeeva-Olga [200]
The “math sentence”: To find the answer, I need to divide the six chocolate bars by 3/4.

To model the situation, you need to draw 6 squares divided into quarters. Color in 3 of the quarters in each square.

Finally, write this for the solution sentence:
By giving 3/4 of a chocolate bar to each of her friends, Mrs. Lopes will be able to share her 6 chocolate bars with 8 different friends.


Hope you get that A+!
3 0
3 years ago
A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the prob
UkoKoshka [18]

Answer:

The probability that 8 mice are​ required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are​ required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

P(X=r)=^nC_r p^rq^{n-r}

Where, p is the probability of success p=\frac{2}{7}

q is the probability of failure q=1-p, q=1-\frac{2}{7}=\frac{5}{7}

n is total number of trials n=8

r=3

Substitute the values,

P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}

P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}

P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}

P(X=3)=0.2428

Therefore, the probability that 8 mice are​ required is 0.2428.

5 0
4 years ago
AB = 3x
Anvisha [2.4K]

Answer:

see explanation

Step-by-step explanation:

If a parallelogram then AB = DC and AD = BC

Equating AB = DC, then

3x = x + 4 ( subtract x from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

Thus

AB = 3x = 3(2) = 6 and DC = x + 4 = 2 + 4 = 6 ⇒ AB = DC

Equating AD and BC, then

2y = y + 2 ( subtract y from both sides )

y = 2

Thus AD = y + 2 = 2 + 2 = 4 and BC = 2y = 2(2) = 4 ⇒ AD = BC

Since opposite sides are congruent then ABCD is a parallelogram

5 0
3 years ago
Read 2 more answers
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