3 years ago

Fill in the blanks below to complete the ratio table.15 _ 1018 6 _

Mathematics

1 answer:

Sidana [21]3 years ago

4 0

Answer:

54-150

Step-by-step explanation:

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Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp

Dimas [21]

Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle $x^2+y^2=9$ in the plane $z=0$ , where the curl is $\mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k$ . Green's theorem applies here, so that

$\displaystyle\iint_S\mathrm{curl}\vec F\cdot\mathrm d\vec S=\int_{\partial S}\vec F\cdot\mathrm d\vec r=3\int_{x^2+y^2=9}\mathrm d\vec r$

which means the value of the line integral is 3 times the area of the circle, or $27\pi$ .

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3 years ago

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Your answer will be
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3 years ago

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galben [10]

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Step-by-step explanation:

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3 years ago

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dangina [55]

Answer:

1. 15-5x 2. 54+18x 3. 3x+15 4. 28x+56

Step-by-step explanation:

I dont get if you need this or the real answer if you need the real answer let me know and I will give you the real answer. :) Have a good day!

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3 years ago

Fill in the blanks below to complete the ratio table.15 _ 1018 6 _​

Fill in the blanks below to complete the ratio table.15 _ 1018 6 _