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dalvyx [7]
2 years ago
9

Find the area of the trapezoid

Mathematics
2 answers:
lidiya [134]2 years ago
4 0

area = ( top rule + bottom rule ) × height / 2

area = ( 2 + 3 ) × 4 / 2

area = 5 × 4 / 2

area = 20 / 2

area = 10

nikdorinn [45]2 years ago
3 0
The area is 10. You can just count the squares and the half squares
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Step-by-step explanation:

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vovikov84 [41]

Answer:

y = 0

Step-by-step explanation:

The given sinusoidal equation is y = 2 \cdot sin \left(\dfrac{\pi}{2} \cdot x + 3 \right)

The general form of the sin function is presented as follows;

y = A·sin(B·(x - C)) + D

Where;

A = The amplitude

The period, T = 2·π/B

The frequency, f = B/2·π

C = The horizontal shift

D = The vertical shift

By comparison with the given sine function, we have;

The amplitude, A = 2

The frequency, f = B/2·π = π/2/(2·π) = 1/4

The frequency, f = 1/4 Hz

C = The horizontal shift = 3/(π/2) = 6/π

The vertical shift, D = 0

Given that the mid line of the parent function, sin(x), is the line y = 0, and that the vertical shift is 0, the midline of the function, y = 2 \cdot sin \left(\dfrac{\pi}{2} \cdot x + 3 \right), is therefore, the line;

y = 0.

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Step-by-step explanation:

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