Answer:
Step-by-step explanation:
Given is an algebraic polynomial of degree 5.

Here leading term is p=3 and constant term is q =12
Factors of p are ±1,±2,±3
Factors of q are 
Possible forms of p/q will be the same for any other polynomial of degree 5 with leading term =3 and constant term = 12
Hence any other polynomial

will have same possible zeroes of p/q, when a,b,c are rational.
Hence any polynomial of this type would have the same possible rational roots.
2
3x. + 63x + 9x + 189
Step-by-step explanation:
<em>Use</em><em> </em><em>distributive</em><em> </em><em>law</em><em>,</em><em> </em><em>in</em><em> </em><em>other</em><em> </em><em>words</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>bracket</em><em> </em><em>terms</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>second</em><em> </em><em>bracket</em><em> </em><em>terms</em><em> </em>
Answer:
Step-by-step explanation:
you have to multiply
Answer:
w <u>> </u> -6
Step-by-step explanation:
divide each term n 2x <u>> </u> -12 by 2 then simplify