Answer:
It has one solution (1,0)
Step-by-step explanation:
y = -2x + 2
y = 4x -4
Substitute the y's
4x - 4 = -2x + 2
Let's move the variables to one side
4x - 4 = -2x + 2
+2x +2x
6x - 4 = 2
Lets move the constant to the other side
6x - 4 = 2
+4 +4
6x = 6
Divide both sides by 6
6x/6 = 6/6
x = 1
Let go back to y = -2x + 2
Substitute the x with 1
y = -2(1) + 2
y = -2 + 2
y = 0
Answer:
fwoggy
Step-by-step explanation:
Answer:
80 ways
Step-by-step explanation:
The first thing is to apply the Fundamental Counting Principle with two groups of items, in this case the multiplication rule is used.
In this case, what we should do is that, for every 1 main course there are 8 appetizers, but there are 10 main courses therefore:
8 * 10 = 80
There are 80 ways to combine appetizers and the main course
1) 5t^2 (1 + 6t)
2) 4x^3y^5 (5x + 2y)
3) (5r + 6x)(5r - 6x)
4) (x + 10)(x - 10)
5) (x - 3)^2
6) (x -5)(x - 3)
7) 3(16r^3 + 9)
8) 8(c^3 + 8d^3)
9) (2r - 125)(4r^2 + 250r + 15625)
10) (c + 3)(c - 1)
