Plz need help i cant do it
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Answer:
The proportion of bricks that crack during the firing process is 0.0001 = 0.01%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean of 925 and a standard deviation of 60 degrees.
This means that
The proportion of bricks that crack during the firing process is closest to
This is 1 subtracted by the pvalue of Z when X = 1150. So
has a pvalue of 0.9999
1 - 0.9999 = 0.0001
The proportion of bricks that crack during the firing process is 0.0001 = 0.01%.