Answer:
If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?
Step-by-step explanation:
First of all, when you want to contrast two hypothesis you need a confidence level p% without which the comparison makes no sense.
In this case, you want to refuse the null hypothesis (the average is 5%) with an alternative one (the average is less than 5%).
You propose a new average (3.6%) based on the evidence.
You cannot prove that the average is actually 3.6%, <em>but if you somehow determine that the probability the average is greater than 3.6% is lower than 100% minus your confidence level p% ,then you can refute the null hypothesis and accept the alternative one as new average.
</em>
So, from the possible choices, the one that fits the best is
If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?
9514 1404 393
Answer:
y = 9x
Step-by-step explanation:
If you like, you can start with the proportion ...
x/y = 0.1/0.9
Multiplying by 9y gives ...
9x = y
The equation you want is ...
y = 9x
Step-by-step explanation:
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Answer:
not enough context or pictures to answer any question
Step-by-step explanation:
but hey, ill take the points
