Answer:
try to do 40 and -40 because those cancel eachother out and make 0
Step-by-step explanation:
Let Cynthia's age be C, then Abigail's age A
since Abigail is 8 years older, her age A = C+8.
20 years ago Cynthia's she was C-20 and Abigail was A-20=3(C-20)
A-20=3C-60
A=3C-40
but we just said A=C+8
so 3C-40=C+8
2C=48
C=24
A=24+8=32
Cynthia's age is 24 and Abigail's age is 32
Answer:
33/90 is the answer
Step-by-step explanation:
exactly what you have there is the procedure
-20 to -14 is 6
-14 to -8 is 6
-8 to -2 is 6
aritmetic sequence
an=a1+d(n-1)
a1=first term
d=common difference
n=which term
first term is -20
common difference is 6
we want 50th term
a50=-20+6(50-1)
a50=-20+6(49)
a50=-20+294
a50=274
the 50th term is 274
Answer:
d = w + 3 (first equation)
2d = 2w + 3 (second equation).
The second equation is equivalent to the first one.
In other words, two equations carry the same information as the first one, not more.
In the language of linear algebra, the system is dependent
