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Hope this helps!!</span>
        
             
        
        
        
Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac. 
ρVg = ρ'V'g + ρ"V"g 
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V'  = ρ'V" - ρV"
(ρ - ρ")V'  = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ) 
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³) 
= (0.9988 g/cm³ ÷ 0.18 g/cm³) 
V'/V" = 5.55
Since V = V' + V"
V' = V - V" 
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55 
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
 
        
             
        
        
        
Answer: this is because with triplet sequences, diversities would be generated and the possibility of overlapping is minimal
Explanation:
 
        
                    
             
        
        
        
Soil and air because it is needed for the development of living beings