Answer:
No invariant point
Step-by-step explanation:
Hello!
When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

1) Let's apply that translation to this polygon, a square. Check it below:
2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.
Examining the graph, we can see that no, there is not an invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.
Answer:
6x+4
Step-by-step explanation:
First thing to do is distribute 1/4 into the parenthesis. So 1/4 times 8x and 16. Which will give you 2x and 4. Then add like terms which will be 2x + 4x which is 6x. Then you have the 4 left over so your new equation is 6x+4.
First off you need to take the square root of both sides and it leaves you with (x)(2x)= 15 then you multiple the x and it gives you 2x^2=15 then you divide by 2 and it gives you 7.5 then you take the square root of that to cancel the x^2 and it gives you x=2.7