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Deffense [45]
3 years ago
5

Somebody help me with this?

Mathematics
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

from top to bottom: 6\sqrt{2}, 2\sqrt{6} , 5\sqrt{2}, 2\sqrt{5}

Step-by-step explanation:

1) 6\sqrt{2} = \sqrt{36} * \sqrt{2} = \sqrt{72} \\2) 2\sqrt{6} = \sqrt{4} * \sqrt{6} = \sqrt{24} \\3) 5\sqrt{2} = \sqrt{25} * \sqrt{2} = \sqrt{50}\\4) 2\sqrt{5} = \sqrt{4} * \sqrt{5} = \sqrt{20}

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Jim can type 90 words in 2.5 minutes on his cell phone. At this rate,how many words can he type in 7.5 minutes
tiny-mole [99]

Answer:

270

Step-by-step explanation:

90 devided by 2.5 = 36 and 36 x 7.5 = 270

7 0
4 years ago
Which term of the arithmetic sequence 1, 5, 9, 13, ... is 169?<br> It is the<br> th term.
sveta [45]

Answer:

43rd term

Step-by-step explanation:

Arithmetic sequences are basically linear functions, so the same value is added every time. So, knowing that Asub1 is equal to one, and Asubn is equal to 169 we can take 169-1 and divide by our common difference. This is four as 5-1=4 and 9-5=4.

So, (169-1)/4=42.

This is however 42 terms after Asub1, so this would be the 43rd teen of the sequence!

8 0
3 years ago
The wind speed near the center of a tornado is represented by the equation S=93logd+65, where d is the distance, in miles, that
Alborosie

Answer:

Step-by-step explanation:

Given

Tornado speed is given by

S=93\log_{10} d+65

where, S=wind Speed

d=distance in miles

if S=130 mph

then

130=93\log_{10} d+65

93\log_{10} d=65

\log_{10} d=0.6989

d=10^{0.699}

d=5.0003\ miles

4 0
4 years ago
Find the perimeter of quadrilateral ABCD. Round to the nearest tenth.
guajiro [1.7K]

Answer:

Perimeter = 13.5 units

Step-by-step explanation:

Coordinates of A → (1, 2)

Coordinates of B → (2, 5)

Coordinates of C → (5, 7)

Coordinates of D → (4, 4)

Length of AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1}})^2}

                      = \sqrt{(2-1)^2+(5-2)^2}=\sqrt{10} units

Length of BC = \sqrt{(5-2)^2+(7-5)^2}

                      = \sqrt{13} units

Length of CD = \sqrt{(5-4)^2+(7-4)^2}=\sqrt{10} units

Length of AC = \sqrt{(4-1)^2+(4-2)^2}=\sqrt{13} units

Perimeter of the quadrilateral = 2(\sqrt{10}+\sqrt{13})

                                                  = 2(3.16 + 3.61)

                                                  = 13.54

                                                  ≈ 13.5 units

Perimeter of the quadrilateral ABCD is 13.5 units

5 0
3 years ago
Ten students share 9 candy bars equally. what fraction of a candy bars does each student get
Solnce55 [7]
I think the answer is 0.9
4 0
4 years ago
Read 2 more answers
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