Ask question

Ask question

All categories

3 years ago

12

Find the midpoint of the segment with endpoints (-4,5) (1,3) and enter its coordinates as an ordered pair. Please help!!!! No li

nks please!!!!

1 answer:

docker41 [41]3 years ago

5 0

Answer:

6-2

Step-by-step explanation:

so first you know you will have to divide it by both numbers you have and whatever number u have thats your answer

You might be interested in

10 watermelons have an average weight of 4.3 pounds and 5 pumpkins have an average weight of 3.4 pounds. What is the average wei

bagirrra123 [75]

Since the average is the sum divided by the count, the sum is the average times the count.

So the sum of the weights of the watermelons is 10(4.3)=43 pounds.

The sum of the weights of the pumpkins are 5(3.4)=17 pounds

The sum of the weight of the fruits is 43+17=60 pounds

Dividing by 15 fruits gives an average item weight of 60/15 = 4 pounds

6 0

3 years ago

Read 2 more answers

The following statement is either true (in all cases) or false (for at least one example). If false, construct a specific e

matrenka [14]

Answer:

False, counterexample below

Step-by-step explanation:

Denote the unit vectors of R^3 by $e_1=(1,0,0), e_2=(0,1,0), e_3=(0,0,1)$ . Now consider $v_1=e_1, v_2=2e_1$ and $v_3=e_3$ . We have that $v_1, v_2,v_3 \in \mathbb{R}^3$ . Also, the vector $v_3$ is not a linear combination of $v_1, v_2$ because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.

However, the set $\{v_1, v_2,v_3\}$ is not linearly independent, because $2v_1-v_2+0v_3=0$ is a non-trivial linear combination of these vectors that equals zero.

4 0

3 years ago

Can someone please help? i don’t know how to solve this.

Charra [1.4K]

Answer:

Hey there!

We have the absolute value of x is greater than two.

Thus, to solve absolute value inequalities, we want to break the inequality down.

We break this down to

x>2

x<-2

Thus, we don't need to simplify this any further, and have our answer.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

Four points from a line are shown in the table below.

Oksi-84 [34.3K]

If it helps at all there is this graphing webpage called desmos.com it helps with tables and a lot of graphing stuff.

8 0

3 years ago

Read 2 more answers

The length of tile B is about 3.87298 inches. Which mark on the tape measure is closest to 3.87298 inches? The tape measure is m

vladimir1956 [14]

Answer:

$\frac{62}{16}$

Step-by-step explanation:

We are given that,

Length of the tile = 3.87298 inches.

The markings on the tape are marked in $\frac{1}{16}$ inches.

As, we see that,

$\frac{64}{16}$ = 4 inches.

So, the required mark will be before than $\frac{64}{16}$ mark.

Since, $\frac{62}{16}$ = 3.875

Hence, the mark closest to 3.87298 inches is $\frac{62}{16}$ .

7 0

2 years ago