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3 years ago

Use the order of operations to simplify 2^3 + 6 1. 19 2. 18 3. 14

Mathematics

1 answer:

igomit [66]3 years ago

6 0

$\huge\text{Hey there!}$

$\mathsf{2^3 + 6}$

$\mathsf{2^3 = 2\times2\times2 = 4\times2=\bf 8}$

$\mathsf{\bf 8}\mathsf{\ +\ 6}$

$\mathsf{\bf = 14}$

$\boxed{\boxed{\large\textsf{Answer: \huge \bf 14}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

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If you are working with less than, or greater than. If there is a negative do you switch the sign? For example 9t-4>32

kirill [66]

Answer:

Rule: If working with an inequality and you either mult. or div. by a negative number, you must reverse the direction of the inequality symbol.

Step-by-step explanation:

Your job here is to simplify 9t-4>32, in which the variable (t) is already positive. Here you do NOT switch signs or reverse the direction of the inequality symbol. Adding 4 to both sides, we get 9t > 36, or t > 4.

If, however, you had -9t-4>32 to work with, the situation would be different because t in this inequality is negative. Adding 4 to both sides results in:

-9t > 36. To solve for t, we must divide both sides by -9 AND reverse the direction of the inequality symbol:

t < -4.

Rule: If working with an inequality and you either mult. or div. by a negative number, you must reverse the direction of the inequality symbol.

8 0

3 years ago

The graph represents y as a function of x . Which additional point can be plotted so that the graph continues to represent y as

tester [92]

Answer:

I think it's the last one D

Step-by-step explanation:

I'm not 100% sure, but I think the x can't repeat and 4 is the only number of x that hasn't been plotted yet. Tell me if it was right?

5 0

3 years ago

Plz help<br>urgent !!!!<br>will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...