final speed of the 3.0 kg cart is 2.67 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 2.0 kg cart moving right at 5.0 on a friction less track collides with a 3.0 kg cart initially at rest. The 2.0 kg cart has a final speed of 1.0 to the left. We will use law of conservation of momentum: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

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Therefore, final speed of the 3.0 kg cart is 2.67 m/s .
Opposite exterior angles are congruent.
DGH = AEG
DGH = 110
You didn’t ummm put a picture
Answer:
ANSWER:
An exponential growth function has constant doubling time.
Step-by-step explanation:
EXPLANATION:
The formula for calculating exponential growth is
A=A'e^kt
here:
A=amount after growth
A'=initial value
e=2.718
k=continuous growth rate
t=time passed
degrees Rankine is about
degrees Celsius, so that

The variance of
is
![\mathrm{Var}[Y]=\mathrm{Var}\left[\dfrac59X-\dfrac{5463}{20}\right]=\dfrac{25}{81}\mathrm{Var}[X]=\dfrac{100}9\approx\boxed{11.1}](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BY%5D%3D%5Cmathrm%7BVar%7D%5Cleft%5B%5Cdfrac59X-%5Cdfrac%7B5463%7D%7B20%7D%5Cright%5D%3D%5Cdfrac%7B25%7D%7B81%7D%5Cmathrm%7BVar%7D%5BX%5D%3D%5Cdfrac%7B100%7D9%5Capprox%5Cboxed%7B11.1%7D)