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3 years ago

Mark earns $550.00 per month. If he spends

Mathematics

2 answers:

andriy [413]3 years ago

8 0

Answer: 40%

Step-by-step explanation:

I would put an explanation but I am supposed to be in class!

kap26 [50]3 years ago

7 0

Answer:

40%

Step-by-step explanation:

Find the percent by dividing 220 by 550

220/550

= 0.4

So, he spends 40% of his monthly income on gas

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If U = {all positive integers) and A = {x|x EU and x is an odd positive integer}, which describes AC?

Galina-37 [17]

Answer:

last choice

Step-by-step explanation:

If we are looking at positive integers and we take out the odd ones, the only one's that are left are the even ones.

So last choice. (Also I assume AC meant the complement of A)

7 0

3 years ago

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Luke mowed a lawn today to earn some extra money. He spent $2.10 on fuel and $4.45 on lunch. He charged $13.50 to mow the lawn.

liberstina [14]

If you add his expenses, $2.10 + $4.45 you’ll get that Luke spent $6.55 today.

Then subtract his expenses by how much he made for mowing the lawn, $13.50 - $6.55 =

Your answer is A. $6.95

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4 years ago

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Sydney makes $12.00 per hour working at GreyStone. Last week he worked 38 hours. What is his gross pay?

telo118 [61]

38 x $12.00 = $456.00

So Sydney's gross pay is A) $456.00.

Hope this Helps!!

7 0

3 years ago

Laura can run 1/4 mile in 82.5 seconds, how long would it take Laura to run 2 and 2/5 miles at that rate

seropon [69]

The correct answer is 792 sec

3 0

3 years ago

In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and

Leviafan [203]

Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

Name the probabilities:

p₁ = 0.02, p₂ = 0.07, p₃ = 0.91

q₁ = 1-p₁ = 0.98 , q₂ = 1-p₂ = 0.93 , q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

The function will follow multinomial distribution:

$f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})$

Substitute the values and make a table.

TABLE IN ATTACHMENT

We calculate marginal distribution by:

$P (X=x)=$ <em>∑</em> $P(X=x,Y=y)$

$fx(x)$ can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

The mathematic expectation E is the sum of product of each possibility with its probabiity.

$E(X)=$ <em>∑ </em> $xP(X=x)$

Find E(X):

$E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)$

$E(X)=0.06$

Condition probability states:

$P(A|B)=\frac{P(A,B)}{P(B)}$

It can also be written as:

$f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}$

Where $f_x(1)\\$ = 0.057624

Calculate the quotient:

$Y|_{x=1}$ = 0 , $f_{Y|_X=1$ = 0.862245

$Y|_{x=1}$ = 1 , $f_{Y|_X=1$ = 0.132653

$Y|_{x=1}$ = 2 , $f_{Y|_X=1$ = 0.000510

$Y|_{x=1}$ = 3 , $f_{Y|_X=1$ = 0

Find the dependency:

$f_{XY}(y)=f_X(x)f_Y(y)$

We found that

$f_{Y|_X=1$ = 0.862245

Calculate $f_Y(1)$ from summing the column from the table

$f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141$

Which are not equal.

Conclusion:

X and Y are NOT Independent

7 0

4 years ago