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2 years ago

Find the slope of each line

Mathematics

1 answer:

Andreyy892 years ago

3 0

Answer:

2/4

Step-by-step explanation:

If you follow the rule, rise over run, you can start from the first point. Then, rise till you reach the level the other point is. (which would be 2) Go over until you meet the second point. (4)

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The product of - 6 and a number x, increased by 23 is – 163. What is<br>the number?

vodka [1.7K]

Answer:

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2 years ago

What is one way to revise for word choice?

VikaD [51]

Answer:

It's C, REVIEW THE EVALUATIVE MODIFIERS

Step-by-step explanation:

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3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

2 years ago

Read 2 more answers

Solve the equation and check your answer. 0.95 t plus 0.05 left parenthesis 100 minus t right parenthesis equals 0.49 left paren

Triss [41]

<h2>Answer:</h2>

The value of t is:

t=48.8889

<h2>Step-by-step explanation:</h2>

We are asked to solve the linear equation in terms of variable t.

The equation is given by:

$0.95t+0.05(100-t)=0.49(100)$

Firstly we will solve the parentheses term in the left and right hand side of the equality as follows:

$0.95t+0.05\times 100-0.05t=49$

Now we combine the like terms on the left side of equality by:

$0.95t-0.05t+5=49\\\\i.e.\\\\0.90t+5=49$

Now we subtract both side of the equation by 5 to get:

$0.90t=44$

Now on dividing both side of the equation by 0.90 we get:

$t=\dfrac{44}{0.90}\\\\i.e.\\\\t=48.8889$

Hence, the value of t is: 48.8889

7 0

3 years ago

Inqualities question pls help!

Margaret [11]

Answer:

Step-by-step explanation:

The closed circle at - $\frac{3}{2}$ indicates that x can equal this value

The open circle at $\frac{7}{2}$ indicates that x cannot equal this value.

All values of x between - $\frac{3}{2}$ and $\frac{7}{2}$ are valid, thus

- $\frac{3}{2}$ ≤ x < $\frac{7}{2}$ → B

5 0

2 years ago