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4 years ago

Calculate the perimeter of a square whose diagonal measures 29 dm.

Mathematics

1 answer:

mojhsa [17]4 years ago

8 0

Answer:

$4\sqrt{420.5}$ dm

Step-by-step explanation:

A square's diagonal cuts across the square, making two right triangles where the diagonal is the hypotenuse.

We have a right triangle with a hypotenuse of 29, and two legs that are the same length (because they are sides of a square)

So, we can use pythagoreans theorem to find the lengths of the legs, or sides of the square.

$a^2 + a^2 = 29^2$

$2a^2 = 841$

$a^2 = 420.5\\$

$a = \sqrt{420.5}$

Now that we have a side length of $\sqrt{420.5}$ , we just have to multiply that by 4, since a square has 4 sides. This leaves us with a final perimeter of:

$4\sqrt{420.5}$

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∠ and ∠ are supplementary angles. If ∠ = (2 − 30)° and ∠ = 4, find the measure of the larger angle

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Answer:

We get ∠A =40° and ∠B = 140° and ∠B = 140° is measure of larger angle

Step-by-step explanation:

we have ∠A = (2x − 30)° and ∠B = 4x, and we need to find measure of larger angle. And ∠A and ∠A are supplementary angles.

If the angles are supplementary there sum is equal to 180° i.e ∠A + ∠B = 180°

So, First we have to find the value of x. and then we can determine larger angle.

We know: ∠A + ∠B = 180

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x=210/6

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So, value of x is x=35

Now finding ∠A and ∠B

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∠A = (2(35) − 30)°

∠A = (70 − 30)°

∠A =40°

and ∠B = 4x

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A realtor earns 1.25%commision on the price of any home she sells last month she sold two homes for a total of $750,000. How muc

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