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svp [43]
3 years ago
9

Cindy shoots a bottle rocket straight up into the air such that its height h, in feet, at time t, in seconds, is given by the fu

nction h of t = negative 16 times t squared plus 85 t + 5.. During what interval will the rocket be at least 43 feet above the ground?
Mathematics
1 answer:
dezoksy [38]3 years ago
6 0

Answer:

t = [0.493,4.2]

Step-by-step explanation:

The height of the rocket straight up into the air is given by :

h(t)=-16t^2+85t+5

We need to find the interval the rocket be at least 43 feet above the ground.

43\ge -16t^2+85t+5\\\\t\ge 0.493\ and\ t\le 4.82\ s

So, the required interval during which the rocket is at least 43 feet above the ground is [0.493,4.2].

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The answer is 573

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t - a number of tens
o - a number of ones

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</span><span>The first and last digits add to make eight: h + o = 8
</span><span>The first two digits add to make twelve: h + t = 12

</span>t + o = 10          ⇒ o = 10 - t
h + o = 8           ⇒ o = 8 - h
_______
10 - t = 8 - h
h + t = 12          ⇒ h = 12 - t
_______
10 - t = 8 - (12 - t)
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h = 12 - t = 12 - 7 = 5
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