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loris [4]
3 years ago
15

Which description best fits the graph

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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How many solutions does this problem have <br> Y=-2x -4<br> Y= 3x plus 3
S_A_V [24]

Answer:

There is one possible solution

Step-by-step explanation:

Here, we want to get the number of solutions

We can proceed to solve the equation

we have two y values so we can directly equate the x parts

-2x - 4 = 3x + 3

3x + 2x = -3-4

5x = -7

x = -7/5

To get y, we substitute

We can only get one value of y too

So we have a point (x,y) as the solution to the system of equations

7 0
2 years ago
An electronics store has two options for liquidating televisions that have not sold. Option 1: decrease the price of each televi
SIZIF [17.4K]

Answer:

Your answer

F(x1) = 350 -17.5x

F(x2) = 350 - 30x

F( x1-x2) = 12.5x

Mark it as Brainlist. Follow me for more answer.

Step-by-step explanation:

3 0
3 years ago
Evaluate.<br><br> 1+5⋅32<br><br> A. 8<br><br> b. 9<br><br> c. 16<br><br> d.18
Anna007 [38]

Answer:

the answer should be 161

6 0
3 years ago
Write the value represented on the number line next to the letter
miss Akunina [59]
Okay, I understand. You found the correct answer. I won't get points. Sniffle.Sniffle.
8 0
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. The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to nd
Blababa [14]

The question is:

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find a second solution y2(x) of the homogeneous equation

x²y'' - 7xy' + 16y = 0; y1 = x^4

Answer:

The second solution y2 is

A(x^4)lnx

Step-by-step explanation:

Given the homogeneous differential equation

x²y'' - 7xy' + 16y = 0

And a solution: y1 = x^4

We need to find a second solution y2 using the method of reduction of order.

Let y2 = uy1

=> y2 = ux^4

Since y2 is also a solution to the differential equation, it also satisfies it.

Differentiate y2 twice in succession with respect to x, to obtain y2' and y2'' and substitute the resulting values into the original differential equation.

y2' = u'. x^4 + u. 4x³

y2'' = u''. x^4 + u'. 4x³ + u'. 4x³ + u. 12x²

= u''. x^4 + u'. 8x³ + u. 12x²

Now, using these values in the original equation,

x²(u''. x^4 + u'. 8x³ + u. 12x²) - 7x(u'. x^4 + u. 4x³)+ 16(ux^4) = 0

x^6u'' + 8x^5u' + 12x^4u - 7x^5u' - 28x^4u + 16x^4u = 0

x^6u'' + x^5u' = 0

xu'' = -u'

Let w = u'

Then w' = u''

So

xw' = -w

w'/w = -1/x

Integrating both sides

lnw = -lnx + C

w = Ae^(-lnx) (where A = e^C)

w = A/x

But w = u'

So,

u' = A/x

Integrating this

u = Alnx

Since

y2 = uy1

We have

y2 = (Alnx)x^4 = (Ax^4)lnx

Therefore, the second solution y2 is

A(x^4)lnx

6 0
3 years ago
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