2 movies
4 hours - .5 popcorn -1.75-1.75=0
Easier terms 4 hours minus 30 min is 3 hours and 30 min left each movie is 1 hour and 45 min plus 1 hour 45 min i that's 2 hours and 90 min 90 min are one hour and 30 min. So 2 hours plus one hour and 30 min is the 3 hours and 30 min are we're left
Answer:
<h2>
3 2/4</h2>
Step-by-step explanation:
5 3/4 - 2 1/4
whole numbers
5 - 2 = 3
fractions
3/4 - 1/4 = 2/4
so
<u><em>3 2/4</em></u> is the answer
C is the answer bc its (5)^2-10(5)+25 so then it is 25-50+25 which = 0
Answer:
The relationship between the lengths of the sides of the triangle is that they all follow the Pythagorean Theorem (at least I'm pretty sure that's the answer.
Step-by-step explanation:
If you plug in the smaller sides like 9^2+40^2 which equals to 1681. Then you square 1681, you'll get 41 as your hypotenuse. The sides of triangle provided above your question, should follow the formula given to you which is c^2=a^2+b^2. Just to be safe, you can check if all of the triangle sides actually are true for the Pythagorean theorem.
Answer:
The rocket hits the gorund after approximately 10.71 seconds.
Step-by-step explanation:
The height of the rocket <em>y</em> in feet <em>x</em> seconds after launch is given by the equation:
![y=-16x^2+165x+69](https://tex.z-dn.net/?f=y%3D-16x%5E2%2B165x%2B69)
And we want to find the time in which the rocket will hit the ground.
When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>
<em />
<em />
We can use the quadratic formula:
![\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
In this case, <em>a</em> = -16, <em>b</em> = 165, and <em>c </em>= 69.
Substitute:
![\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-165%5Cpm%5Csqrt%7B%28165%29%5E2-4%28-16%29%2869%29%7D%7D%7B2%28-16%29%7D)
Evaluate:
![\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-165%5Cpm%5Csqrt%7B31641%7D%7D%7B-32%7D%3D%5Cfrac%7B165%5Cpm%5Csqrt%7B31641%7D%7D%7B32%7D)
Hence, our solutions are:
![\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x_1%3D%5Cfrac%7B165%2B%5Csqrt%7B31641%7D%7D%7B32%7D%5Capprox%2010.71%5Ctext%7B%20or%20%7D%20x_2%3D%5Cfrac%7B165-%5Csqrt%7B31641%7D%7D%7B32%7D%5Capprox-0.40)
Since time cannot be negative, we can ignore the first answer.
So, the rocket hits the gorund after approximately 10.71 seconds.