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Tema [17]
2 years ago
9

The EDI ____________layer describes the business application that i

Computers and Technology
1 answer:
suter [353]2 years ago
6 0

Answer:

a) EDI Semantic Layer

Explanation:

EDI is an acronym for electronic data interchange and it can be defined as a form of communication between interconnected computer systems and software applications with respect to business informations in standard digital formats.

This ultimately implies that, electronic data interchange (EDI) involves the transfer of business informations such as financial transactions between the computer systems of various organizations such as banks, companies, governmental agencies, etc. Thus, it avails businesses the ability to create strategic communications using computer to computer links to effectively and efficiently exchange business informations electronically or in digital formats.

Hence, the EDI Semantic layer describes the business application that is driving electronic data interchange (EDI).

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What is the reddish-brown substance in the water?
Mariulka [41]

Answer:

iron

Your water might be affected by iron, which is a commonly-occurring constituent of drinking water. Iron tends to add a rusty, reddish-brown (or sometimes yellow) color to water. If the color is more black than red, your water might contain a combination of iron and manganese.

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3 years ago
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What term is defined as software that allows users to use and adapt it for any purpose, often allowing the public to participate
Alex787 [66]

Answer:

The answer is open source

Explanation:

hope this helps

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6 0
2 years ago
Write a function that returns a chessboard pattern ("B" for black squares, "W" for white squares). The function takes a number N
Kryger [21]

Answer:

Here is the C++ program.

#include <iostream>  //to use input output functions

using namespace std;  // to access objects like cin cout

 

void chessboard(int N){  // function that takes a number N as parameter generates corresponding board

   int i, j;  

   string black = "B";  // B for black squares

   string white = "W"; // W for white squares

   for(i=1;i<=N;i++){  //iterates through each column of the board

       for(j=1;j<=N;j++){  //iterates through each row of the board

           if((i+j)%2==0)  // if sum of i and j is completely divisible by 2

               cout<<black<<" ";  //displays B when above if condition is true

           else  //if (i+j)%2 is not equal to 0

           cout<<white<<" ";  }  // displays W when above if condition is false

      cout<<endl;    }    }  //prints the new line

       

int main(){    //start of the main function

   int num;  //declares an integer num

   cout << "Enter an integer representing the size of the chessboard: ";  //prompts user to enter size of chess board

   cin >> num;  //reads value of num from user

   chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop  for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

8 0
2 years ago
The formatting option functions like space bar. However instead of moving one space at a time, it allows you to move your text i
Schach [20]
What are the options???
4 0
3 years ago
You currently have 15 switches with an average of 20 stations connected to each switch. The switches are connected to one anothe
vampirchik [111]

Answer:

Reorganize the network into smaller groups and connect each group to a router.

Explanation:

The user presently has 15 switches linked to another switch, with such an avg of 20 locations. The switches are linked to each other in such a manner that almost all systems can convey within a single Local area network. The high percentage to broadcast frames were found on that Local area network. They believe the amount of broadcasts could affect throughput.

So, they would reorganize each network into smaller units and link to such a router for each unit.

4 0
3 years ago
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