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Brums [2.3K]
3 years ago
12

Pls help math!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0
The answer is b 4






correct answer
yawa3891 [41]3 years ago
3 0

Answer:

B. 4

Step-by-step explanation:

Cross multiply:

1x64 and 16 times x gives you 16x = 64.

Now solve for x. 16 x 4 is 64 so x is equal to 4.

Hope it helps!

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Suppose A = {1, 7, 13, 17, 21, 25} and B = {7, ,14, 21, 28, 35, 42}. What is A∩B?
Lubov Fominskaja [6]

A\cap B=\{7,21\}

8 0
4 years ago
Which of these must be true
Bingel [31]
B) Line HI and FI are congruent

because they are both the radius of the circles and their central angles are also congruent.
6 0
3 years ago
Each side of a square is (7 + 3x) units. Which is the perimeter of the square?
storchak [24]
The perimeter is 4(7+3x) which is
= to 12x+28
3 0
3 years ago
A force of 7 lb is required to hold a spring stretched 9 in. beyond its natural length. How much work W is done in stretching it
Ymorist [56]

144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Force F=10 lb

From the hookes Law

F=kx

Therefore, calculate k for the spring for

10=k(\frac{4}{12}) = > k=\frac{120}{4}=30

Work done in stretching a spring through a length dx is

dW=F.dx = > dW=kxdx

For calculating the work done for stretching the spring to x=6in=(6/12)feet beyond the natural length, Integrate over the limits of x=0 to x=1/2

Therefore,

\int_{0}^{W}dW=\int_{0}^{0.5}kxdx = > W=\frac{1}{2}k[x^2]_{0}^{0.5}=\frac{1}{2}30 \times (0.5)^2=\frac{30}{8}

That is,

W=\frac{15}{4} ft-lb\\

The answer that is given is for stretching the spring to 4 inches.

Mass of 10 m of chain length is 80kg. This implies, Mass per unit meter length of the chain is

m_{l}=\frac{80}{10}=8kg/m

Consider a small length dx of the chain at the end point A. Work done in lifting the small length dx over the height of x meters is

dW=(8g)dx \times x=8gxdx

Now, integrate over the the value of x from

x=0 when end of the chain A is on the ground

x=6 when end of the chain A reaches 6 m above the ground

That is,

\int_{0}^{W}dW=\int_{0}^{6}8gxdx=8g [\frac{x^2}{2}]_{0}^{6}=4g(6^2-0^2)

W=4g \times 36=144g \ Joules

Hence,144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Learn more about Integration here brainly.com/question/2263647

#SPJ4

7 0
2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
slamgirl [31]

x = Alicia's age

Amy is 8 years older than twice her cousin Alicia's age so Amy's age = 2x + 8

Sum of their ages is less than 32

x + 2x + 8 < 32

3x + 8 < 32

3x < 24

x < 8

So Alicia's age is greater than 0 but less than 8 years old

(0 < x < 8)

Answer:

A) 0 < x < 8


4 0
3 years ago
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